- [Instructor] We're asked to So, the first step is using the dot product to get a vertical vector that will be used in step 2. First, here's the midpoint of line segment KK': Plug these coordinates into the equation y = 2x 4 to see whether they work. With step 1 my partial formula is: 2 ( a + ( a ) n n) mind the change of sign of a above, we "flipped" it When a figure is reflected over a random line, it is reflected in such a way that the whole figure is not flipped over any axis, and some part of the figure remains on the same axis. If you're behind a web filter, please make sure that the domains *.kastatic.org and *.kasandbox.org are unblocked. Because the perpendicular bisector of a segment goes through the segment's midpoint, the first thing you need to do to find the equation of the reflecting line is to find the midpoint of line segment JJ': Next, you need the slope of line segment JJ': Now you can finish the first part of the problem by plugging the slope of 2 and the point (5, 6) into the point-slope form for the equation of a line: That's the equation of the reflecting line, in slope-intercept form. Are there any canonical examples of the Prime Directive being broken that aren't shown on screen? So let's see, C and C prime, how far apart are they from each other? Thus we have Use slope point form to find equation of the line and find its interaection with given line. \frac{1}{2} & -\frac{\sqrt{3}}{2} \end{array} \right)$$. Save my name, email, and website in this browser for the next time I comment. Example 1: A polygon with the vertices $A = (-10,6)$ , $B = (-8,2)$, $C = (-4,4)$ and $D = (-6,7)$ is reflected over the x-axis. That is, $Ax=x$. We can calculate Mid-point between the points as: Mid point $= (\dfrac{x_{1} + x_{2}}{2}),(\dfrac{y_{1} + y_{2}}{2})$, Midpoint of $A$ and $A^{} = (\dfrac{5 + 5}{2}),(\dfrac{6 6 }{2}) = (5,0 )$, Mid point of $B$ and $B^{}$ = $(\dfrac{3 + 3}{2}),(\dfrac{2 2 }{2}) = (3,0 )$, Mid point of $C$ and $C^{}$ = $(\dfrac{8 + 8}{2}),(\dfrac{5 5 }{2}) = (8,0 )$. If I want my conlang's compound words not to exceed 3-4 syllables in length, what kind of phonology should my conlang have? So then divide six by two to get 3. ","hasArticle":false,"_links":{"self":"https://dummies-api.dummies.com/v2/authors/8957"}}],"_links":{"self":"https://dummies-api.dummies.com/v2/books/"}},"collections":[],"articleAds":{"footerAd":"
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